Solve the inequality and show the graph of the solution on number line:
$3 x - 2 < 2 x + 1$

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Solution

Given, $3 x - 2 < 2 x + 1$
$\Rightarrow 3 x - 2 x < 1 + 2$
$\Rightarrow x < 3 or x \in (- \infty, 3)$
The lines $y = 3 x - 2$ and $y = 2 x + 1$ both will intersect at $x = 3$
Clearly, the dark line shows the solution of $3 x - 2 < 2 x + 1$ .

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