1
Question
Solve the linear equation:3(5z−7)−2(9z−11)=4(8z−13)−17
Solve the linear equation:3(5z−7)−2(9z−11)=4(8z−13)−17
Open in App
Solution
The correct option is C. z=2
We have,3(5z−7)−2(9z−11)=4(8z−13)−17
⇒15z−21−18z+22=32z−52−17
⇒−3z+1=32z−69
⇒−3z−32z=−69−1 [Transposing 32z to LHS and 1 to RHS]
⇒−35z=−70
⇒z=−70−35=2
Hence, value of z=2.
The correct option is C. z=2
We have,3(5z−7)−2(9z−11)=4(8z−13)−17
⇒15z−21−18z+22=32z−52−17
⇒−3z+1=32z−69
⇒−3z−32z=−69−1 [Transposing 32z to LHS and 1 to RHS]
⇒−35z=−70
⇒z=−70−35=2
Hence, value of z=2.
Suggest Corrections
14
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
