Question

Solve the linear equation:

$\frac{(2x+3)-(5x-7)}{6x+11}=-\frac{8}{3}$

• A. $x=\frac{-11}{31}$
• B. $x=\frac{102}{19}$
• C. $x=\frac{-23}{5}$
• D. $x=\frac{-118}{39}$

Answer 1

The correct option is D $x=\frac{-118}{39}$

$Wehave,\frac{(2x+3)-(5x-7)}{6x+11}=-\frac{8}{3}⟹\frac{-3x+10}{6x+11}=-\frac{8}{3}⟹3(-3x+10)=-8(6x+11)[Bycross-multiplication]⟹-9x+30=-48x-88⟹-9x+48x=-88-30⟹39x=-118or,x=\frac{-118}{39}$