Question

Solve the pair of linear equation
$\begin{array}{c}8x-3y=1\\ 34x-3y=4\end{array}$

Answer 1

$8x-3y=1$ ...(i)

$34x-3y=4$ ...(ii)

subtracting eqn. (i) from (ii), we get,

$(34x-3y)-(8x-3y)=4-1$

$26x=3$

$x=\frac{3}{26}$

Substituting the value of $x$ in eqn.(i),

$[8\times (\frac{3}{26}\left)\right]-3y=1$

$y=\frac{-1}{39}$

Solution:

$x=\frac{3}{26}$

$y=\frac{-1}{39}$