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Question

Solve the pair of linear equations xy=28 and x3y=0 and if the solution satisfies, y=mx+5, then find m.

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Solution

given xy=28,x3y=0

28+y=3y

2y=28,y=14

therefore x=42

now substituting these values in y=mx+5

we get 14=42m+5,m=942

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