Question

Solve the quadratic equation $100x^2-20x+1=0$ by factorisation.

Answer 1

We have, $100x^2-20x+1=0$

$$\begin{gathered} \Rightarrow 100x^2-10x-10x+1=0 \\ \Rightarrow 10x(10x-1)-1(10x-1)=0 \\ \Rightarrow (10x-1)(10x-1)=0 \end{gathered}$$

Either, $$\begin{gathered} 10x-1=0\text{or}10x-1=0 \\ \Rightarrow x=\frac{1}{10}\text{or}x=\frac{1}{10} \end{gathered}$$

Hence, $\mathit{x}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{1}}{\mathbf{10}}$ is the solution of given quadratic equation.