Question

Solve the quadratic equation

$36x^2-12ax+(a^2-b^2)=0$

Answer 1

$36x^2-12ax+(a^2-b^2)=0$

$A{x}^2+Bx+C=0$ from,

$A=36$ $B=-12a$ $C=(a^2-b^2)$

Roots of quadratic equation formula :

$x=\frac{-B\pm \sqrt{B^2-4AC}}{2A}$

$=\frac{12a\pm \sqrt{144a^2-144(a^2-b^2)}}{2\times 36}$

$=\frac{12a\pm \sqrt{144b^2}}{72}$

$=\frac{12a\pm 12b}{72}$

$=\frac{a\pm b}{6}$

$\Rightarrow x=\frac{a+b}{6}$ or $\frac{a-b}{6}$