Question

Solve the quadratic equation : $4x^2-4ax+(a^2-b^2)=0$

Answer 1

$4x^2-4ax+(a^2-b^2)=0$

$⟹4x^2-4ax+a^2=b^2$

$⟹(2x-a{)}^2=b^2$

$⟹2x-a=\pm b$

$⟹2x=a\pm b$

$⟹Rootsofgivenquadraticequationare:$

$x_1=\frac{a+b}{2},x_2=\frac{a-b}{2}$