Question

Solve the quadratic equation: $-7x^2+2x+9=0$

Answer 1

Consider the given equation.

$-7x^2+2x+9=0$

$byu\sin gformulax=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-2\pm \sqrt{2^2-\left(4.-7.9\right)}}{2.-7}=\frac{-2\pm \sqrt{4+252}}{-14}=\frac{-2\pm \sqrt{256}}{-14}=\frac{-2\pm 16}{-14}=\frac{-2+16}{-14}or,\frac{-2-16}{-14}=-1or\frac{-18}{-14}=\frac{9}{7}$

Hence, this is the answer.