Question

Solve this:
Q.11. A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm. The retarding potential required to stop the escape of photo electron is
(1) 4.81 V
(2) 3.74 V
(3) 2.65 V
(4) 1.07 V

Answer 1

Dear Student,


$$\begin{gathered} \phi =1.07eV,\lambda =332nm \\ maximumKE=\frac{hc}{\lambda }-\phi =\frac{4.136*{10}^{-15}*3*{10}^8}{332*{10}^{-9}}-1.07=2.667eV \\ voltagerequiredtostopetheelectronV=\frac{2.667eV}{e}=2.667V \\ option3 \\ Regards \end{gathered}$$