Question

Solve this:
Q.25. A particle has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. The sum of these displacements is
1) 12 m
2) 10.04 m
3) 14.31 m
4) None of these

Answer 1

Dear Student,



$$\begin{gathered} totaldisplacement \\ d=\sqrt{{12}^2+5^2+6^2}=\sqrt{144+25+36}=\sqrt{205}=14.32m \\ Regards \end{gathered}$$