Question

Solve this:
Q.4. Flux $\varphi$ (in weber) in a closed circuit of resistance 10 ohm varies with time t (in second) according to the equation $\varphi$ = $6t^2-5t+1$. What is the magnitude of the induced current at t = 0.25 s?
(1) 1.2 A
(2) 0.2 A
(3) 0.6 A
(4) 0.8 A

Answer 1

Dear student,


$$\begin{gathered} \varphi =6t^2-5t+1 \\ E=\frac{-d\varphi }{dt}=-\left(12t-5\right) \\ i=\frac{E}{r}=\frac{-\left(12t-5\right)}{10}fort=0.25sec. \\ i=\frac{-\left(12*0.25-5\right)}{10}=0.2A \\ REgards \end{gathered}$$