Question

Solve :
$\underset{x\to \pi }{lim}\frac{sin(\pi -x)}{\pi (\pi -x)}$

Answer 1

We have,

${lim}_{x\to \pi }\frac{\sin (\pi -x)}{\pi (\pi -x)}$

We know that

${lim}_{x\to 0}\frac{\sin x}{x}=1$

Therefore,

$=\frac{1}{\pi }\times 1$

$=\frac{1}{\pi }$

Hence, this is the answer.