Solve using cross multiplication
5x − 3y = 26
4x + 2y = 34
(7,3)
Given equations-
5x − 3y = 26
4x + 2y = 34
a1=5,b1=−3,c1=−26 and a2=4,b2=2, c2=−34
x y 1
-3 -26 5 -3
2 -34 4 2
we have xb1c2−b2c1 = yc1a2−a2c1 = 1a1b2−b2a1
⇒ x102+52 = y−104+170 = 110+12
⇒ x154 = y66 = 122
⇒ x154 = 122 ⇒ x = 7
⇒ y66 = 122 ⇒ y = 3