Question

Solve using formula.
$x^2-3x-2=0$.

Answer 1

$x^2-3x-2=0$

$a=1,b=-3,c=-2$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-3)\pm \sqrt{{(-3)}^2-4\cdot 1(-2)}}{2\cdot 1}$

$x=\frac{3\pm \sqrt{17}}{2}$