Solve : $x^{2} - 2 x - 15 = 0.$

x = 3, 5

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x = - 5, 3

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x = 5, - 3

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x = - 3, - 5

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Solution

The correct option is D $x = 5, - 3$
Given, $x^{2} - 2 x - 15 = 0$

$⟹ x^{2} - 5 x + 3 x - 15 = 0$

$⟹ x (x - 5) + 3 (x - 5) = 0$

$⟹ (x - 5) (x + 3) = 0$

$⟹ x = 5, - 3$

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