Solve - x2 - 3-2 - 2i x - 6-2 i - 0-

Given, x^2 (3√(2)+2i)x+6√(2)i=0 (a+bi)^2 (3√(2)+2i)(a+bi)+6√(2)i=0 (a^2 b^2 3√(2)a+2b)+i( 2a+2ab+6√(2) 3√(2)b)=0+0i [ a^2 b^2 3√(2)a+2b=0; ...

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Complex Numbers

Solve : x2 -...

Question

Solve : $x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2} i = 0$ .

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x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2 i} = 0

x^{2} - (3 \sqrt{2} - 2 i) x - \sqrt{2} i = 0

Solve the following quadratic equations by factorization method :

(i) $x^{2} + 10 i x - 21 = 0$

(ii) $x^{2} + (1 - 2 i) x - 2 i = 0$

(iii) $x^{2} - (2 \sqrt{3} + 3 i) x + 6 \sqrt{3} i = 0$

(iv) $6 x^{2} - 17 i x - 12 = 0$

Solve the following quadratic equations :

(i) $x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2} i = 0$

(ii) $x^{2} - (5 - i) x + (18 + i) = 0$

(iii) $(2 + i) x^{2} - (5 - i) x + 2 (1 - i) = 0$

(iv) $x^{2} - (2 + i) x - (1 - 7 i) = 0$

(v) $i x^{2} - 4 x - 4 i = 0$

(vi) $x^{2} + 4 i x - 4 = 0$

(vii) $2 x^{2} + \sqrt{15} i x - i = 0$

(viii) $x^{2} - x + (1 + i) = 0$

(ix) $i x^{2} - x + 12 i = 0$

(x) $x^{2} - (3 \sqrt{2} - 2 i) x - \sqrt{2} i = 0$

(xi) $x^{2} - (\sqrt{2} + i) x + \sqrt{2} i = 0$

(xii) $2 x^{2} - (3 + 7 i) x + (9 i - 3) = 0$

x^{2} + 10 i x - 21 = 0

x^{2} + (1 - 2 i) x - 2 i = 0

x^{2} - (2 \sqrt{3} + 3 i) x + 6 \sqrt{3} i = 0

6 x^{2} - 17 i x - 12 = 0

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