Solve- x2-7 x-12 -x-4

The correct option is B (x 3)(x^2 7x +12)÷(x 4) Factorizing the dividend, (x^2 7x +12), we get, (x^2 7x +12) = (x^2 3x 4x +12) ( 7x is split as 3x ...

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Standard VIII

Mathematics

Factorisation

Solve: x2-7 x...

Question

Solve: $(x^{2} - 7 x + 12) \div (x - 4)$

(x - 4)

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(x - 3)

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(x + 4)

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(x + 3)

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Solution

The correct option is B $(x - 3)$
$(x^{2} - 7 x + 12) \div (x - 4)$
Factorizing the dividend, $(x^{2} - 7 x + 12)$ , we get,
$(x^{2} - 7 x + 12) = (x^{2} - 3 x - 4 x + 12)$
( -7x is split as -3x -4x)
Taking the common factors,
$(x^{2} - 3 x - 4 x + 12) \div (x - 4)$
$= x (x - 3) - 4 (x - 3) \div (x - 4)$
$= (x - 3) \times (x - 4) \div (x - 4)$
$= (x - 3)$

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Similar questions

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Solve: (x2−7x+12)÷(x−4)

The correct option is B (x−3)(x2−7x+12)÷(x−4) Factorizing the dividend, (x2−7x+12), we get, (x2−7x+12)=(x2−3x−4x+12) ( -7x is split as -3x -4x) Taking the common factors, (x2−3x−4x+12)÷(x−4) =x(x−3)−4(x−3)÷(x−4) =(x−3)×(x−4)÷(x−4) =(x−3)

Solve: $(x^{2} - 7 x + 12) \div (x - 4)$