Now, x^2 7x+60=0 ⇒ x^2 12x 5x+60=0 ⇒ x(x 12) 5(x 12)=0 ⇒ (x 5)(x 12)=0 ⇒ x=5,12 . ...

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Zeroes of a Polynomial

Solve; x2-7x...

Question

Solve;
$x^{2} - 7 x + 60 = 0$ .

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Solution

Now,
$x^{2} - 7 x + 60 = 0$

$\Rightarrow x^{2} - 12 x - 5 x + 60 = 0$

$\Rightarrow x (x - 12) - 5 (x - 12) = 0$

$\Rightarrow (x - 5) (x - 12) = 0$

$\Rightarrow x = 5, 12$ .

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