Solve: x-3 (2+x) $>$ 2(3x-1)

Open in App

Solution

$x - 3 (2 + x) > 2 (3 x - 1)$
$\Rightarrow x - 6 - 3 x > 6 x - 2$
$\Rightarrow - 2 x - 6 > 6 x - 2$
$\Rightarrow - 2 x - 6 x > - 2 + 6$
$\Rightarrow - 8 x > 4$
$\Rightarrow - x > \frac{4}{8} = \frac{1}{2}$
$\Rightarrow x < \frac{- 1}{2}$
$∴ x \in (- \infty, \frac{- 1}{2})$

Suggest Corrections

Similar questions

x

2^{3 x + 3} = 2^{3 x + 1} + 48

5 x - 2 (2 x - 3) = 2 (3 x - 1) + \frac{5}{2}

l i m x \to 0 \frac{3^{2 x} - 1}{2^{3 x} - 1}

{sin}^{2} x + \frac{1}{4} {sin}^{2} 3 x = sin x \cdot {sin}^{2} 3 x

Solve for $x$ :- $2^{5 x - 1} = 4 \times 2^{3 x + 1}$

Join BYJU'S Learning Program