Solve:
$x - 3 y = 19 x - 5 y = - 7$

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Solution

Let $x - 3 y = 19 \dots (1) x - 5 y = - 7 \dots (2)$
$(1) - (2)$
$x - 3 y - 19 - x + 5 y + 7 = 0 2 y - 12 = 0 2 y = 12 y = 6$
Put it in $(1)$
$x - 3 (6) = 19 x = 19 + 18 x = 37$

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