Solve: $(x - 4)^{2} + 5^{2} = 12^{2}$ .

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Solution

${(x - 4)}^{2} + 5^{2} = 12^{2}$

${(x - 4)}^{2} = 12^{2} - 5^{2}$

${(x - 4)}^{2} = 119$

$x - 4 = \sqrt{119}$

$x = \sqrt{119} + 4$

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⎡ ⎣ \sqrt{\frac{15^{2}}{27^{2}}} - \sqrt{\frac{5^{2}}{12^{2}}} ⎤ ⎦

\times \sqrt{\frac{9^{2}}{4^{2}}}

(x + 4)^{2} - (x - 5)^{2} = 9

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} + . . . . . . = 21^{2}

5^{2} + . . . . . + 30^{2} = 31^{2}

6^{2} + 7^{2} + . . . . . . = . . . . . . . .

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} +

= 21^{2}

5^{2} +

+ 30^{2} = 31^{2}

6^{2} + 7^{2} +

=

(\sqrt[4]{(x)^{- 12}})^{2 / 3}

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