Question

Solve x :$4x²-2(a²+b²)x+a²b²$

Answer 1

$4x²-(2a^2+2b^2)x+a^2{b}^2=0$
$\Rightarrow 4x²-2a²x-2b²x+a²b²=0$
$\Rightarrow 2x(2x-a²)-b²(2x-a²)=0$
$\Rightarrow (2x-a²)(2x-b²)=0$
$\Rightarrow 2x-a²=0,2x-b²=0$
$\Rightarrow 2x=a²,2x=b²$
$\Rightarrow x=a²/2,x=b²/2$