Solve x and y using substitution method: √7x +√13y=0 ; √5x +√17y=0

Open in App

Solution

√7x + √13y = 0 ...(1)
√5x + √17y = 0 ...(2)

From (1),
√7x = –√13y

x = –√13y / √7

Substituting x ' s value in (2)

√5 ( –√13y / √7 ) + √17y = 0

–√65y + √119y = 0

√54 y = 0y = 0

Putting y = 0 in (1)

√7x + √13(0) = 0

√7x + 0 = 0

√7x = 0x = 0

x=0

ths the answer is x=0 and y=0

Suggest Corrections

Similar questions

x - y = 3

x + y = 0

Solve the pair of equations using the method of substitution 3x-y = 8 ,5x+y = 0 [2 MARKS]

3 x + y + 1 = 0

3 x - 4 y = 10

\frac{1}{x} + \frac{1}{y} = 4

\frac{2}{x} + \frac{3}{y} = 7, x \neq 0, y \neq 0

Join BYJU'S Learning Program