Consider given the expression, #10; #10;Let, #10; #10; y=x^c+e^x+e^e #10; #10;Differentiate with respect to x, #10; #10; ddxy=ddx( #1 ...

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Particular Solution of a Differential Equation

Solve: xe+ex...

Question

Solve:
$x^{e} + e^{x} + e^{e}$

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Solution

Consider given the expression,

Let,

$y = x^{c} + e^{x} + e^{e}$

Differentiate with respect to x,

$\frac{d}{d x} y = \frac{d}{d x} (x^{c} + e^{x} + e^{e})$

$= c . x^{c - 1} + e^{x} + 0$

$\frac{d y}{d x} = c . x^{c - 1} + e^{x}$

Hence, this is the answer.

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