Solve:
$x + y = 18$ ; $y + z = 12$ ; $z + x = 16$

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Solution

x+y = 18 ; y+z = 12 ;z+x = 16.
x = 18-y $∴$ z+18-y = 16 $\Rightarrow$ y-z = z & y + z = 12
adding -
2y=14 $\Rightarrow$ y = 7 & z = 5
$∴$ x = 18-7 = 11
$∴$ x = 11, y = 7 & z = 5

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