Solve
$y^{2} - \frac{1}{8 y^{2}}$

Open in App

Solution

$= y^{2} - {(\frac{1}{2 \sqrt{2} y})}^{2}$
$= (y + \frac{1}{2 \sqrt{2} y}) (y - \frac{1}{2 \sqrt{2} y})$

Suggest Corrections

Similar questions

13 x^{2} - 12 y^{2} = 40; 6 x^{2} - 8 y^{2} = 16

x^{2} + y^{2}

\frac{16 y^{2} - 20 y + 9}{8 y^{2} + 12 y + 21} = \frac{4 y - 5}{2 y + 3}

x^{2} - y^{2} = 9

x^{3} y + 4 x^{2} y^{2} + 3 x y^{3} + 7 x^{2} y^{2} + 3 x^{3} + 4 y^{2} + 6 x y + 7 x^{3} y + 8 y^{2}

\frac{d y}{d x} + \sqrt{\frac{1 - y^{2}}{(1 + y)^{2}}} = 0

Join BYJU'S Learning Program