Some pale~green crystals are strongly heated. The gases given off are passed into a container surrounded by ice and then through a solution of acidified $K M n O_{4}$ . The $K M n O_{4}$ is decolorized, a waxy white solid is formed in the ice container; this is dissolved in water. The solution will:

Give a precipitate with silver nitrate solution

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Give a precipitate with barium chloride solution

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Turn red litmus blue

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Give blue color with starch solution

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Solution

The correct option is C Give a precipitate with barium chloride solution
Option (B) is correct.
The solution will gives a precipitate with barium chloride solution.
Assume green crystal of $F e S O_{4}$ $F e S O_{4} Δ - \to F e_{2} O_{3} + S O_{2} + S O_{3}$ $S O_{2} + M n O_{4}^{-} ⟶ M n^{2 +} + S O_{4}^{2 -}$ $S O_{3}$ form waxy white solid $(H_{2} S O_{4})$ in ice container which is dissolved in water and gives $S O_{4}^{2 -}$ ion. When $B a C l_{2}$ react with $S O_{4}^{2 -}$ ion, it forms white ppt. of $B a S O_{4}$ .

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Some pale~green crystals are strongly heated. The gases given off are passed into a container surrounded by ice and then through a solution of acidified KMnO4. The KMnO4 is decolorized, a waxy white solid is formed in the ice container; this is dissolved in water. The solution will: