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Question

Some positive charge is spread uniformly over the surface of a thin spherical shell. Radius of sphere is 100 cm and electric field on the surface is 90×103 N/C. A point A is at 50 cm from the centre & point B is at 150 cm from the centre. Field at A & B are EA & EB respectively, then

A
EA=EB=45×103 N/C
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B
EA=0,EB=45×103 N/C
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C
EA=0,EB=40×103 N/C
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D
EA=EB=40×103 N/C
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Solution

The correct option is C EA=0,EB=40×103 N/CThe point A lies inside the shell, EA=Einside=0 The point B is outside the sphere, EB=kqr2=kq(3R/2)2 =49(kqR2) =49×Esurface =49×90×103 =40×103 N/C

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