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Question

Some solution are given in List - I and Some Properties are given in List - II, Match the list - I with list - II.

List-I List-II
(A) π1:0.1M glucose
π2:0.1M Urea
(P) π1 and π2 Isotonic
(B)
π1:0.1M NaCl
π2:0.1M Na2SO4
(Q) No net migration of solvent across the membrane
(C)
π1:0.1M NaCl
π2:0.1M KCl
(R) π1hypertonic to π2
(D)
π1:0.1M CuSO4
π2:0.1M Sucrose
(S) π1hypotonic to π2

Which of the following option has the correct combination considering List - I and List - II.

A
A, P
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B
B,R
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C
C, S
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D
D, Q
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Solution

The correct option is A A, P
(A)
π1:0.1M glucosei=1{ for non- elecrolyte i=1}
π2:0.1M Ureai=1
π1:CRT =0.1RT
π2:CRT =0.1RT
π1=π2(π1 and π2 isotonic )
So, no net migration of solvent across the membrane.

(B)
π1:0.1M NaCli=2
π2:0.1M Na2SO4i=3
π1:i CRT=2×0.1RT=0.2RT
π2:0.1×3RT=0.3 RT
π1<π2
π1 hypotonic to π2.

(C)
π1:0.1M NaCl i=2
π2:0.1M KCl i=2
π1=π2=2×0.1RT=0.2RT
π2 & π2 isotonic
So, no net migration of solvent across the membrane.

(D)
π1:0.1M CuSO4 i=2
π2:0.1M Sucrose i=1
π1:2×0.1RT=0.2RT
π2:2×0.1RT=0.1RT
π1>π2
So π1 is hypertonic to π2

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