CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Some solutions are given in List -I and Some Properties are given in List-II, Match the list-I with List-II.

List-I List-II
(A) π1:0.1M glucose
π2:0.1M Urea
(P) π1 and π2 Isotonic
(B)
π1:0.1M NaCl
π2:0.1M Na2SO4
(Q) No net migration of solvent across the membrane
(C)
π1:0.1M NaCl
π2:0.1M KCl
(R) π1hypertonic to π2
(D)
π1:0.1M CuSO4
π2:0.1M Sucrose
(S) π1hypotonic to π2

Which of the following options has the incorrect combination considering List-I

A
A,R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
B,S
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
C,Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
D,R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A A,R
(A)
π1:0.1M glucosei=1{ for non- elecrolyte i=1}
π2:0.1M Ureai=1
π1:CRT =0.1RT
π2:CRT =0.1RT
π1=π2(π1 and π2 isotonic )
So, no net migration of solvent across the membrane.

(B)
π1:0.1M NaCli=2
π2:0.1M Na2SO4i=3
π1:i CRT=2×0.1RT=0.2RT
π2:0.1×3RT=0.3 RT
π1<π2
π1 hypotonic to π2.

(C)
π1:0.1M NaCl i=2
π2:0.1M KCl i=2
π1=π2=2×0.1RT=0.2RT
π2 & π2 isotonic
So, no net migration of solvent across the membrane.

(D)
π1:0.1M CuSO4 i=2
π2:0.1M Sucrose i=1
π1:2×0.1RT=0.2RT
π2:2×0.1RT=0.1RT
π1>π2
So π1 is hypertonic to π2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Structural Organization of Cells
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon