Question

riya has 4 times as many two-rupee coins as she has 5 rupee. if she has in all a sum of rs.182' how many coins of each denominals does she have?

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{number}\mathrm{of}\mathrm{five}\mathrm{rupee}\mathrm{coin}\mathrm{be}\mathrm{x} \\ \mathrm{Then}\mathrm{Number}\mathrm{of}\mathrm{two}\mathrm{ruppe}\mathrm{coin}=4\mathrm{x} \\ \mathrm{A}.\mathrm{T}.\mathrm{Q} \\ 2\left(4\mathrm{x}\right)+5\left(\mathrm{x}\right)=182 \\ \Rightarrow 8\mathrm{x}+5\mathrm{x}=182 \\ \Rightarrow 13\mathrm{x}=182 \\ \Rightarrow \mathrm{x}=14 \\ \mathrm{So},\mathbf{number}\mathbf{}\mathbf{of}\mathbf{}\mathbf{five}\mathbf{}\mathbf{rupee}\mathbf{}\mathbf{coin}\mathbf{=}\mathbf{14} \\ \mathbf{and}\mathbf{}\mathbf{number}\mathbf{}\mathbf{of}\mathbf{}\mathbf{two}\mathbf{}\mathbf{rupee}\mathbf{}\mathbf{coin}\mathbf{=}\mathbf{4}\mathbf{x}\mathbf{=}\mathbf{4}\mathbf{\times }\mathbf{14}\mathbf{=}\mathbf{56} \end{gathered}$$