An electron moving with the speed of 5 times- 104 m-s enters into an electric field and attains a uniform acceleration of 1015 m-s2 in the direction of motion- In how much time- will it attain a speed twice of its initial speed- In this time- how much distance will it cover- nbsp- nbsp-

Dear Student, Initial velocity of the electron is, u = 5 times; 104 m/s Acceleration of the electron is, a = 104 m/s2 (i) Using, v = u + at = gt; 2u = u + ...

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Standard IX

Physics

Acceleration

An electron m...

Question

An electron moving with the speed of 5 × 10⁴ m/s enters into an electric field and attains a uniform acceleration of 10¹⁵ m/s² in the direction of motion. In how much time, will it attain a speed twice of its initial speed? In this time, how much distance will it cover?

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Solution

Dear Student,

Initial velocity of the electron is, u = 5 × 10⁴ m/s

Acceleration of the electron is, a = 10⁴ m/s²

(i)

Using, v = u + at

=> 2u = u + at

=> t = u/a = (5 × 10⁴)/( 10⁴) = 5 s

(ii)

Distance travelled in this time is,

S = ut + ½ at²

=> S = (5 × 10⁴) × 5 + ½ × 10⁴ × 5²

=> S = 375000 m

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An electron moving with the speed of 5 × 104 m/s enters into an electric field and attains a uniform acceleration of 1015 m/s2 in the direction of motion. In how much time, will it attain a speed twice of its initial speed? In this time, how much distance will it cover?

An electron moving with the speed of 5 × 10⁴ m/s enters into an electric field and attains a uniform acceleration of 10¹⁵ m/s² in the direction of motion. In how much time, will it attain a speed twice of its initial speed? In this time, how much distance will it cover?