Question

Solve this:

​Q125. A body is released from a great height and falls freely towards the earth. Another body is released from same exactly one later. The separation between the two bodies, two seconds after the release of the second body is

(a) 4.9 m (b) 9.8 m (c) 19.6 m (d) 24.5 m

Answer 1

$$\begin{gathered} dis\tan cetravelfirstbodyin3sec. \\ x=\frac{9.8*3^2}{2} \\ dis\tan cetravelbysecondbodyin2sec \\ x\text{'}=\frac{9.8*2^2}{2} \\ dustnacebetweenthem=\frac{9.8*3^2}{2}-\frac{9.8*2^2}{2}=\frac{9.8*5}{2}=24.5m \\ Regards \end{gathered}$$