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Standard XII

Chemistry

Multi-Electron Configurations and Orbital Diagrams

3Solve this: ...

Question

3Solve this:

A compound C (molecular formula, C₂H₄O₂) reacts with the non metal
compound R and evolves a gas which burn with a pop sound, compound
treatment with an alcohol A in the presence of an acid form a sweet
compound S(molecular formula, C3H₆O₂ On addition Of NaOH to C. it also
and water S on treatment with NaOH solution gives back Rand A, Identified
and write down the reactions involved.

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Solution

Compound C is CH₃COOH.
Compound R is CH₃COONa
Compound A is CH₃OH
Compound S is CH₃COOCH₃
Chemical reaction in sequence are as follows:
CH₃COOH + Na →CH₃COONa + H₂
CH₃OH + CH₃COOH+ acid ⇒ CH₃COOCH₃ + H₂O
CH₃COOH + NaOH → CH₃COONa + H₂O
CH₃COOCH₃ + NaOH → CH₃COONa + CH₃OH

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Compound C is CH3COOH. Compound R is CH3COONa Compound A is CH3OH Compound S is CH3COOCH3 Chemical reaction in sequence are as follows: CH3COOH + Na →CH3COONa + H2 CH3OH + CH3COOH+ acid ⇒ CH3COOCH3 + H2O CH3COOH + NaOH → CH3COONa + H2O CH3COOCH3 + NaOH → CH3COONa + CH3OH