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Dear student, nbsp; molality of solution = nbsp; n / W (in kg) nbsp; = nbsp; 18/180/1 nbsp; =0.1 m nbsp; nbsp; as we know that nbsp; #8710; ...

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Factors Affecting Boiling Point

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$Q . 18 g g l u \cos e d i s s o l v e i n 1 k g o f w a t e r i n a c o n t a i n e r a t w h a t t e m p e r a t u r e t h e w a t e r b o i l a t 1.013 b a r p r e s s u r e K b f o r w a t e r = 0.52 K K g m o l^{- 1}]$

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C_{6} H_{12} O_{6}

K_{b}

m o l^{- 1}

18 g

(C_{6} H_{12} O_{6})

1 k g

1.013 b a r

K_{b}

0.52 K k g m o l^{- 1}

18 g

C_{6} H_{12} O_{6}

1 k g

K_{b}

0.52 K k g m o l^{- 1}

18 g

C_{6} H_{12} O_{6}

m o l^{- 1})

1 k g

K_{b}

0.52 K k g m o l^{- 1}

373.15 K

18 g

C_{6} H_{12} O_{6}

= 180 g / m o l

1 k g

[K_{b}

= 0.52 K k g m o l^{- 1}

= 373.15 K

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