Question

Solve this:

Q. An inductor coil stores U energy when i current is passed through it and dissipates energy at the rate of P. The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is

$\left(1\right)\frac{4\mathrm{U}}{\mathrm{P}}\left(2\right)\frac{\mathrm{U}}{\mathrm{P}}\left(3\right)\frac{2\mathrm{U}}{\mathrm{P}}\left(4\right)\frac{2\mathrm{P}}{\mathrm{U}}$

Answer 1

$$\begin{gathered} Dearstudent, \\ U=\frac{1}{2}L{I}^2 \\ P=I^{2}R \\ L=\frac{2U}{I^2} \\ R=\frac{P}{I^2} \\ Timecons\tan t=\frac{L}{R}=\frac{2U}{P} \\ Regards \end{gathered}$$