Solve this-47- Ratio of coefficients of K2Cr2O7 and KI in the reaction- K2Cr2O7-KI-H2SO4 -8594-Cr2-SO4-3-H2O-I2 is- nbsp-a- 3-1 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -b- 1-3 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp-c- 6-1 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -d- 1-6

Dear student, nbsp; nbsp; the above reaction is given as : K2Cr2O7 nbsp; + 7H2SO4 + 6KI nbsp; rarr; 4K2SO4 nbsp; + Cr2(SO4)3 nbsp; + 3I2 + 7H2O ...

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Introduction to Electrophilic Substitution

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47. Ratio of coefficients of K₂Cr₂O₇ and KI in the reaction, K₂Cr₂O₇+KI+H₂SO₄ $\to$ Cr₂(SO₄)₃+H₂O+I₂ is:
(a) 3:1 (b) 1:3 (c) 6:1 (d) 1:6

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