Question

Speed of sound in air is 350 $m{s}^{-1}$, fundamental frequency of an open organ pipe of 50 cm length will be

• A. 175 Hz
• B. 350 Hz
• C. 700 Hz
• D. 500 Hz

Answer 1

The correct option is B 350 Hz

Fundamental frequency of an open organ pipe is given by ,

$n_1=v/\lambda =v/2l$ ,

where $v=$speed of sound in air ($=350m/s,given$),

$\lambda =$ wavelength ,

$l=$ length of organ pipe ($=50cm=0.50m$ , given) ,

therefore , $n_1=350/(2\times 0.50)=350Hz$