The speed of sound in air is 350 m $s^{- 1}$ , The fundamental frequency of an open pipe 50 cm long will be

50 Hz

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175 Hz

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350 Hz

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700 Hz

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Solution

The correct option is B 350 Hz
Given: velocity of sound in air $v = 350 m / s$
Length of the open organ pipe $L = 50 c m = 0.5 m$
Fundamental frequency in an open organ pipe $ν_{1} = \frac{v}{2 L} = \frac{350}{2 \times 0.5}$
Thus $ν_{1} = 350 H z$

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If the velocity of sound in air is 350 m/s. Then the fundamental frequency of an open organ pipe of length 50 cm, will be

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