Speed of sound in air is $350 m s^{- 1}$ , fundamental frequency of an open organ pipe of $50$ cm length will be

175 H z

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350 H z

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700 H z

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500 H z

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Solution

The correct option is B $350 H z$
Fundamental frequency of an open organ pipe is given by ,
$n_{1} = v / λ = v / 2 l$ ,
where $v =$ speed of sound in air ( $= 350 m / s, g i v e n$ ),
$λ =$ wavelength ,
$l =$ length of organ pipe ( $= 50 c m = 0.50 m$ , given) ,
therefore , $n_{1} = 350 / (2 \times 0.50) = 350 H z$

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Speed of sound in air is 350ms−1, fundamental frequency of an open organ pipe of 50cm length will be

The correct option is B 350HzFundamental frequency of an open organ pipe is given by , n1=v/λ=v/2l ,where v=speed of sound in air (=350m/s,given), λ= wavelength , l= length of organ pipe (=50cm=0.50m , given) ,therefore , n1=350/(2×0.50)=350Hz

Speed of sound in air is $350 m s^{- 1}$ , fundamental frequency of an open organ pipe of $50$ cm length will be