-1-d2ydx23-2-dydx1-3Find it-s order and degree-

The correct option is A 2, 3 Consider the given equation. #10; #10; √(1+( d^2ydx^2 #10;)^3)=( 2+dydx)^1/3 #10; #10; #160; #10; #10;On ...

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Higher Order Derivatives

√1+d2ydx23=2+...

Question

$\sqrt{1 + {(\frac{d^{2} y}{d x^{2}})}^{3}} = {(2 + \frac{d y}{d x})}^{1 / 3}$
Find it's order and degree.

2, 3

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2, 9

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2, 6

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2, 2

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Solution

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Similar questions

\sqrt{1 + {(\frac{d^{2} y}{d x^{2}})}^{3}} = {(2 + \frac{d y}{d x})}^{1 / 3}

x^{2} = \frac{{(1 + {(\frac{d y}{d x})}^{2})}^{3 / 2}}{\frac{d^{2} y}{d x^{2}}}

y = 1 + {(\frac{d y}{d x})}^{1} + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . . .

\frac{d^{2} y}{d x^{2}} = x l o g (\frac{d y}{d x})

\frac{{(1 + {(\frac{d y}{d x})}^{2})}^{\frac{3}{2}}}{\frac{d^{2} y}{d x^{2}}} = c

{(\frac{d y}{d x})}^{3} + 5 x = {(\frac{d^{2} y}{d x^{2}})}^{3 / 2}

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