The correct option is C √(2 + √(2 + 2 cos 4θ)) = √(2 + √(2.2cos^2 2θ)) = √(2 + 2cos 2θ) = √(4 cos^2 θ) = 2cosθ. ...

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Higher Order Derivatives

√2+√2+2 cos 4...

Question

$\sqrt{2 + \sqrt{2 + 2 c o s 4 θ}}$ =

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Solution

The correct option is C

$\sqrt{2 + \sqrt{2 + 2 c o s 4 θ}}$ = $\sqrt{2 + \sqrt{2.2 c o s^{2} 2 θ}}$

= $\sqrt{2 + 2 c o s 2 θ}$ = $\sqrt{4 c o s^{2} θ}$ = $2 c o s θ$ .

Suggest Corrections

Similar questions

\sqrt{2 + \sqrt{2 + 2 cos 4 θ}} = 2 cos θ

Prove that:

$\sqrt{2 + \sqrt{2 + 2 c o s 4 θ}} = 2 c o s θ$

\sqrt{2 + \sqrt{2 + 2 c o s 4 θ}}

\sqrt{2 + \sqrt{2 + 2 \cos 4 θ}} = 2 \cos θ

2 cos θ = \sqrt{2 + \sqrt{(2 + 2 cos 4 θ)}}

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