$\sqrt{- 2} \sqrt{- 3} =$
[Roorkee 1978]

\sqrt{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \sqrt{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

i \sqrt{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $- \sqrt{6}$
$\sqrt{- 2} \sqrt{- 3} = i \sqrt{2} i \sqrt{3} = i^{2} \sqrt{6} = - \sqrt{6}$

Suggest Corrections

Similar questions

\sqrt{- 2} \sqrt{- 3} =

$\int_{0}^{\frac{π}{2}} e^{x} s i n x d x =$ [Roorkee 1978]

$\int_{0}^{\frac{x}{2}} \frac{x + s i n x}{1 + c o s x} d x =$ [Roorkee 1978]

$\int_{0}^{\frac{π}{2}} e^{x} s i n x d x =$ [Roorkee 1978]

Join BYJU'S Learning Program