$\sqrt{- 2} \sqrt{- 3} =$
[Roorkee 1978]

\sqrt{6}

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- \sqrt{6}

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i \sqrt{6}

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None of these

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Solution

The correct option is B $- \sqrt{6}$
$\sqrt{- 2} \sqrt{- 3} = i \sqrt{2} i \sqrt{3} = i^{2} \sqrt{6} = - \sqrt{6}$

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[IIT 1978; EAMCET 1992; Roorkee 1998; JMI EEE 2001]

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