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Byju's Answer
Standard VIII
Mathematics
Laws of Exponents
√36a4b6144a6b...
Question
√
36
a
4
b
6
144
a
6
b
4
= ?
A
∣
∣
∣
1
2
b
a
∣
∣
∣
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B
2
∣
∣
∣
b
a
∣
∣
∣
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C
1
2
∣
∣
∣
b
a
∣
∣
∣
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D
3
2
∣
∣
∣
b
a
∣
∣
∣
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Solution
The correct option is
C
1
2
∣
∣
∣
b
a
∣
∣
∣
Here,
√
36
a
4
b
6
144
a
6
b
4
=
√
36
b
2
144
a
2
=
6
12
√
(
b
a
)
2
=
1
2
∣
∣
∣
b
a
∣
∣
∣
Suggest Corrections
0
Similar questions
Q.
Solve:
∣
∣ ∣ ∣
∣
1
+
a
2
−
b
2
2
a
b
−
2
b
2
a
b
1
−
a
2
+
b
2
2
a
2
b
−
2
a
1
−
a
2
−
b
2
∣
∣ ∣ ∣
∣
=
(
1
+
a
2
+
b
2
)
3
.
Q.
By using properties of determination, show that
∣
∣ ∣ ∣
∣
1
+
a
2
−
b
2
2
a
b
−
2
b
2
a
b
1
−
a
2
+
b
2
−
2
b
2
b
−
2
a
1
−
a
2
−
b
2
∣
∣ ∣ ∣
∣
=
(
1
+
a
2
+
b
2
)
3
Q.
∣
∣ ∣ ∣
∣
1
+
a
2
−
b
2
2
a
b
−
2
b
2
a
b
1
−
a
2
+
b
2
2
a
2
b
−
2
a
1
−
a
2
−
b
2
∣
∣ ∣ ∣
∣
=
(
1
+
a
2
+
b
2
)
3
Q.
√
3
−
1
√
3
+
1
=
a
−
b
√
3
then the values of a and b are
Q.
Using properties of determinants, prove that:
∣
∣ ∣ ∣
∣
1
+
a
2
−
b
2
2
a
b
−
2
b
2
a
b
1
−
a
2
+
b
2
2
a
2
b
−
2
a
1
−
a
2
−
b
2
∣
∣ ∣ ∣
∣
=
(
1
+
a
2
+
b
2
)
3
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