-1-cos A -1-cos A -Select all that apply-A- A-tan AB- cosec A- AC- 1-cos A -sin AD- 1-cos A -sin A

The correct options are B cosec A+cot A D 1+cos A/sin A √(1+cos A/1−cos A) = √((1+cos A)(1+cos A)/(1−cos A)(1+cos A)) = √((1+cos A)^2/(1−cos^2 A)) = √((1+cos ...

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Byju's Answer

Standard X

Mathematics

Trigonometric Identities

√1+cos A /1-c...

Question

$\sqrt{\frac{1 + c o s A}{1 - c o s A}}$ = ?

Select all that apply.

$s e c A + t a n A$

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$c o s e c A + c o t A$

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$\frac{1 - c o s A}{s i n A}$

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$\frac{1 + c o s A}{s i n A}$

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Solution

The correct options are
B
$c o s e c A + c o t A$

D
$\frac{1 + c o s A}{s i n A}$

$\sqrt{\frac{1 + c o s A}{1 - c o s A}}$

= $\sqrt{\frac{(1 + c o s A) (1 + c o s A)}{(1 - c o s A) (1 + c o s A)}}$

= $\sqrt{\frac{(1 + c o s A)^{2}}{(1 - c o s^{2} A)}}$

= $\sqrt{\frac{(1 + c o s A)^{2}}{(s i n^{2} A)}}$

= $\frac{1 + c o s A}{s i n A}$

= $\frac{1}{s i n A} + \frac{c o s A}{s i n A}$

= $c o s e c A + c o t A$

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√1+cosA1−cosA = ? Select all that apply.

The correct options are B cosecA+cotA D 1+cosAsinA √1+cosA1−cosA = √(1+cosA)(1+cosA)(1−cosA)(1+cosA) = √(1+cosA)2(1−cos2A) = √(1+cosA)2(sin2A) = 1+cosAsinA = 1sinA+cosAsinA = cosecA+cotA

$\sqrt{\frac{1 + c o s A}{1 - c o s A}}$ = ?

Select all that apply.