The correct option is D 5 (√(6) √(1)2)^2+(√(2)+6)^2 = (?)^3 69 (√(6))^2+(√(1)2)^2 2×√(6)×√(12) + (√(2))^2+(6)^2+2×√(2)×6 = (?)^3 69 6+12 √(2×2×6×12)+2+36+12√(2 ...

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Quadratic Equations

√6-√1 22+√2+6...

Question

$(\sqrt{6} - \sqrt{1} 2)^{2} + (\sqrt{2} + 6)^{2} = (?)^{3} - 69$

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Solution

The correct option is D
5

$(\sqrt{6} - \sqrt{1} 2)^{2} + (\sqrt{2} + 6)^{2} = (?)^{3} - 69$

$(\sqrt{6})^{2} + (\sqrt{1} 2)^{2} - 2 \times \sqrt{6} \times \sqrt{12} + (\sqrt{2})^{2} + (6)^{2} + 2 \times \sqrt{2} \times 6 = (?)^{3} - 69$
$6 + 12 - \sqrt{2 \times 2 \times 6 \times 12} + 2 + 36 + 12 \sqrt{2} = (?)^{3} - 69$
$18 - 12 \sqrt{2} + 38 + 12 \sqrt{2} = (?)^{3} - 69$
$56 = (?)^{3} - 69$
$56 + 69 = (?)^{3}$
$125 = (?)^{3}$
$(5)^{3} = (?)^{3}$
$? = 5$

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Question 6
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