Question

Srivani walks $12m$ due East and turns left and walks another $5m$, how far is she from the place she started?

Answer 1

From fig.,

Required distance $=AC=\sqrt{{AB}^2+{BC}^2}=\sqrt{{\left(12\right)}^2+{\left(5\right)}^2}=\sqrt{144+25}=\sqrt{169}=13$

Hence Srivani is $13m$ far from the place she started.