Stability of following alkenes in the increasing order is -

I < I I I < I V < I I

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I < I I < I I I < I V

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I V < I I I < I I < I

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I I < I I I < I V < I

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Solution

The correct option is A $I < I I I < I V < I I$
Stability of alkenes is decided by number of hyper conjugations (hydrogens) attached to it.
As refer to the above image, $I I$ is highly stable because carbanions are highly stable in $I I^{n d}$ configuration. Trans alkene stable because of less repulsions.
$I I > I V > I I I > I$

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Stability of following alkenes in the increasing order is -

The correct option is A I<III<IV<IIStability of alkenes is decided by number of hyper conjugations (hydrogens) attached to it.As refer to the above image, II is highly stable because carbanions are highly stable in IInd configuration. Trans alkene stable because of less repulsions.II>IV>III>I